(5x^2)+x=130

Solution for (5x^2)+x=130 equation:

(5x^2)+x=130

We move all terms to the left:

(5x^2)+x-(130)=0

a = 5; b = 1; c = -130;
Δ = b2-4ac
Δ = 12-4·5·(-130)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-51}{2*5}=\frac{-52}{10}
=-5+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+51}{2*5}=\frac{50}{10}
=5
$